(8x+3)(x^2-4x+1)=

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Solution for (8x+3)(x^2-4x+1)= equation: 


Simplifying
(8x + 3)(x2 + -4x + 1) = 0

Reorder the terms:
(3 + 8x)(x2 + -4x + 1) = 0

Reorder the terms:
(3 + 8x)(1 + -4x + x2) = 0

Multiply (3 + 8x) * (1 + -4x + x2)
(3(1 + -4x + x2) + 8x * (1 + -4x + x2)) = 0
((1 * 3 + -4x * 3 + x2 * 3) + 8x * (1 + -4x + x2)) = 0
((3 + -12x + 3x2) + 8x * (1 + -4x + x2)) = 0
(3 + -12x + 3x2 + (1 * 8x + -4x * 8x + x2 * 8x)) = 0
(3 + -12x + 3x2 + (8x + -32x2 + 8x3)) = 0

Reorder the terms:
(3 + -12x + 8x + 3x2 + -32x2 + 8x3) = 0

Combine like terms: -12x + 8x = -4x
(3 + -4x + 3x2 + -32x2 + 8x3) = 0

Combine like terms: 3x2 + -32x2 = -29x2
(3 + -4x + -29x2 + 8x3) = 0

Solving
3 + -4x + -29x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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